0(t)=16t^2+8

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Solution for 0(t)=16t^2+8 equation: 



0(t)=16t^2+8

We move all terms to the left:

0(t)-(16t^2+8)=0

We add all the numbers together, and all the variables

t-(16t^2+8)=0

We get rid of parentheses

-16t^2+t-8=0

a = -16; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·(-16)·(-8)
Δ = -511
Delta is less than zero, so there is no solution for the equation

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